(Hi)A right triangle has an area of 48cm^2, and one side that is twice as the other side. what is the hypotenuse of this triangle?

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- Oct 13th 2010, 08:59 PMbatki610geometry (traingle)
(Hi)A right triangle has an area of 48cm^2, and one side that is twice as the other side. what is the hypotenuse of this triangle?

- Oct 13th 2010, 09:03 PMEducated
The area of a triangle = 1/2*b*h

b = 2x

h = x

Area = 48

Can you solve it now? - Oct 14th 2010, 06:02 AMbatki610
No, unfortunately I dont get it! If you can please show me with steps that would be very helpful.

- Oct 14th 2010, 07:34 AMPlato
In any right triangle with leg of lengths $\displaystyle a~\&~b$ its area is $\displaystyle \dfrac{a\cdot b}{2}$.

In your triangle we know that $\displaystyle a=2b$ thus its area is just $\displaystyle b^2$.

We also know that $\displaystyle c^2=a^2+b^2$ where $\displaystyle c$ is the length of the hypotenuse.

You need to finish it off.