# geometry (traingle)

• October 13th 2010, 08:59 PM
batki610
geometry (traingle)
(Hi)A right triangle has an area of 48cm^2, and one side that is twice as the other side. what is the hypotenuse of this triangle?
• October 13th 2010, 09:03 PM
Educated
The area of a triangle = 1/2*b*h

b = 2x
h = x
Area = 48

Can you solve it now?
• October 14th 2010, 06:02 AM
batki610
No, unfortunately I dont get it! If you can please show me with steps that would be very helpful.
• October 14th 2010, 07:34 AM
Plato
In any right triangle with leg of lengths $a~\&~b$ its area is $\dfrac{a\cdot b}{2}$.
In your triangle we know that $a=2b$ thus its area is just $b^2$.
We also know that $c^2=a^2+b^2$ where $c$ is the length of the hypotenuse.

You need to finish it off.