I have an obtuse triangle. It has sides 6, 8, and x. The angle opposite side x is an obtuse angle. What could be some possible values of side x?
I know there is a rule for obtuse angles that is: (a^2) + (b^2) < c^2.
So could 15 be an answer? 36 + 100 < 225
Thanks for helping!
An obtuse angle may be larger than a right angle by an arbitrarily small amount. Hence the greatest lower bound is 10, as in that side will definitely exceed 10 and might be smaller than any value greater than 10. I should have explained this clearly.