The diagram shows a logo $\displaystyle ABCD$ in the shape of a trapezium. $\displaystyle AB=13x cm, CD=12x cm, AD=2y cm $ and Angle $\displaystyle BCD = 90^o$. The shaded region PQDR is a parallelogram such that $\displaystyle RD=\frac{1}{3}AD$.

Before reaching the part i have problems with,

$\displaystyle BC=2y+5x$ and area of $\displaystyle ABCD=\frac{1}{2}(4y+5x)(6x)$

The question is Find the area of PQDR