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Math Help - Ratio of Circle Radii that Share tangent lines

  1. #1
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    Ratio of Circle Radii that Share tangent lines

    I don't know how to explain the arrangement, so I've attached an image. Forgive my notation, I'm not used to writing math problems.

    The points that are black are known. The points that are red are unknown. P_0T_{11} and P_0T_{12} are tangent to BOTH circles. P_1P_2 is tangent only to circle 2 (the larger circle).

    Conceptually, I think this is easy. The center of circle 2 ( C_2) lies on P_0P_2, and the radius is such that it is tangent to both C_1 and C_2. Without any other conditions, there would be an infinite number of solutions. However, there is an additional line that bounds circle 2. So, unless I am mistaken, there is now only one solution.

    However, I don't know what I'm doing wrong. I've tried using similar triangles, but because neither C_2 nor the radius for circle 2 is known, I haven't been able to determine the ratio of the two triangles. In fact, everything I've tried seems to require a system of equations.

    So I tried the following, where d(\textbf{x}_0,\textbf{x}_1) is the distance formula between points \textbf{x}_0 and \textbf{x}_1:
    d(P_0,T_2_1)=d(P_0,T_2_2)
    d(P_1,T_2_2)=d(P_1,T_3)
    d(P_0,T_2_2)+d(T_2_2,P_1)=d(P_0,P_1)

    However, when I write the distance formulas for three dimensions, I end up with nine unknowns; three for each of the following points, T_2_1, T_2_2, and T_3.

    So, I tried an additional three equations based on the distance of the center of circle 2 to each of the bounding lines using the following formula:
    d=\dfrac{\mid(\textbf{x}_0-\textbf{x}_1)\times(\textbf{x}_0-\textbf{x}_2)\mid}{\mid\textbf{x}_2-\textbf{x}_1\mid}

    I needed three more equations, so I tried parameterizing the equation for P_0P_1, yielding:
    x_{T_{22}}=x_{P_0}+t(x_{P_1}-x_{P_0})
    y_{T_{22}}=y_{P_0}+t(y_{P_1}-y_{P_0})
    z_{T_{22}}=z_{P_0}+t(z_{P_1}-z_{P_0})

    where t=\dfrac{d(P_0,T_{22})}{d(P_0,P_1)}

    However, this led to a binomial equation in x, y and z. So, instead I tried using the equation for each of the three bounding lines, since the respective tangent point is a solution to the corresponding line equation. Unfortunately, I'm not sure if I'm not solving the system of equations correctly, or if my equations are not independent from each other.

    Again, I feel like there should be an elegant solution to this. Perhaps something similar to finding the tangent points of a circle inscribed inside a triangle.

    Any help would be greatly appreciated.
    Attached Thumbnails Attached Thumbnails Ratio of Circle Radii that Share tangent lines-circleproblem.png  
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  2. #2
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    Hi arcanine, welcome to MHF.

    P1 and P2 are known points.

    Find the equation of the tangent P1P2.

    Write it in the form y = mx + c.

    Condition for line to be a tangent to a circle C2 is

    c^2 = r_{2}^2(1 + m^2)

    find r2. T11 is the radius of C1. Now find the ratio of r1 and r2.
    Last edited by sa-ri-ga-ma; October 5th 2010 at 03:44 AM.
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  3. #3
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    I'm not sure I understand your post

    Quote Originally Posted by sa-ri-ga-ma View Post
    Find the equation of the tangent P1P2.

    Write it in the form y = mx + c.
    In this case, P_1 and P_2 have the same y-coordinates, so,
    y=c=y_{P_1}

    Condition for line to be a tangent to a circle C2 is

    c^2 = r_{2}^2(1 + m^2)

    find r2. T11 is the radius of C1. Now find the ratio of r1 and r2.
    When using the above equation, I get a result that is not the radius of circle 2 (See Attached Image). Also note that Circle 3 does not pass through C_1, and if it did, it would only be a coincidence.
    Attached Thumbnails Attached Thumbnails Ratio of Circle Radii that Share tangent lines-circleproblem2.png  
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  4. #4
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    In the problem you have mensioned that P1 and P2 are known points. (The points that are black are known) Is it so?

    Then how can be their y-coordinates are the same? In the picture they are not the same.
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  5. #5
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    Quote Originally Posted by sa-ri-ga-ma View Post
    In the problem you have mensioned that P1 and P2 are known points. (The points that are black are known) Is it so?
    Yes, it is so. Perhaps my assumptions are not standard, but I was assuming that the y-axis was a vertical line on the screen, and the x-axis was a horizontal line on the screen, such that they are perpendicular to eachother. Under that assumption, the y-coords for P_1 and P_2 are the same.

    However, I'm not too concerned with their y-coordinates. I'm more interested in how you derived the equation for a line tangent to a circle, because it is not giving the correct radius of the circle, as mentioned in post #3. An important note is that the origin is at an arbitrary location.

    Without actually writing things out, it appears that the equation you provided for a line tangent to a circle assumes that the circle's center is at the origin. If this were the case, I wouldn't have any problems, because C_2 would become a known point.
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  6. #6
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    Assuming P_1P_2 is horizontal, then C_2T_3 is vertical, and the equation for the line is x = a for some value of a. Now the line T_{22}C_2 is perpendicular to P_0P_1 and therefore you know its slope m_2.

    So since P_0P_2, C_2T_3 and T_{22}C_2 all intersect at the same point, you have:

    T_{22}C_2: y = m_2x + b_2
    P_0P_2: y = m_1x + b_1
    C_2T_3: x = a
    P_1P_2: y = b
    P_0P_1: y = m_3x + b_3

    Therefore the point of intersection can be written:
    (a, m_1a + b_1)

    where a and b_2 are the only unknowns.

    Now, m_1a + b_1 = m_2a + b_2, which yields
    b_2 = (m_1 - m_2)a + b_1

    Continuing, we find the point of intersection of P_0P_1 and T_{22}C_2 in terms of a:

    m_2x + b_2 = m_3x + b_3
    m_2x + (m_1 - m_2)a + b_1 = m_3x + b_3
    (m_2 - m_3)x = b_3 - (m_1 - m_2)a
    x_0 = \frac{b_3 - (m_1 - m_2)a}{m_2 - m_3}
    y_0 = \frac{m_3(b_3 - (m_1 - m_2)a)}{m_2 - m_3} + b_3

    Now the distances T_{22}C_2 and T_3C_2 must be equal, therefore \sqrt{(a - x_0)^2 + (m_1a + b_1 - y_0)^2} = m_1a + b_1 - b. Since everything is in terms of a or known constants, solve the equation for a and then you will know the location of every unknown point.
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  7. #7
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    As you have guessed, I have assumed that Po is the origin. When you say that some points are known, you must mention the poisition of the origin.
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  8. #8
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    Quote Originally Posted by sa-ri-ga-ma View Post
    When you say that some points are known, you must mention the poisition of the origin.
    I apologize, I'm new to describing math problems.

    I've looked at icemanfan's solution, and I believe it will work. I haven't crunched through the math to be sure, but at first glance it looks good.

    Thanks everyone for the help.
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