Find the relationship describing the volume (V) of a cube as a function of the length of the diagonal going through the cube (d). and evaluate it for a diagonal length of d = 1.2.
Find the relationship describing the volume (V) of a cube as a function of the length of the diagonal going through the cube (d). and evaluate it for a diagonal length of d = 1.2.
Pythagoras' theorem will give you this.
If you have a regular cube of side length "x", the volume is $\displaystyle x^3$
The diagonal across the base square has length $\displaystyle \sqrt{x^2+x^2}=\sqrt{2x^2}=\sqrt{2}x$
The diagonal going through the cube has length $\displaystyle \sqrt{2x^2+x^2}=\sqrt{3x^2}=\sqrt{3}x$
$\displaystyle \displaystyle\ V=x^3=\frac{\left(\sqrt{3}x\right)^3}{\left(\sqrt{ 3}\right)^3}$
$\displaystyle =\displaystyle\frac{d^3}{\left(\sqrt{3}\right)^3}= \left(\frac{d}{\sqrt{3}}\right)^3$
You can then perform your calculation.
After applying Pythagoras' theorem twice, we get... "internal diagonal"= $\displaystyle x\sqrt{3}$
where "x" is the length of a side of the cube.
The volume of the cube is $\displaystyle x^3$
Since $\displaystyle \displaystyle\frac{\sqrt{3}}{\sqrt{3}}=1$
then $\displaystyle \displaystyle\frac{(x\sqrt{3})^3}{(\sqrt{3})^3}=x^ 3$
which is the cube volume.
This allows us to express the cube volume as a function of the internal diagonal length.
The internal diagonal goes from the bottom right-corner of the base of the cube to the
top-left corner of the facing side,
or from the bottom left-corner to the facing side's top right-corner.
I'll be the first to admit that my sketch is not drawn well!
The sides should appear to be the same lengths.