If you are given the sphere: x²+y²+z²+x-6z=0 and the plane x+y+=0

how do you find the planes which are parallell to that plane which intersect the sphere to create circles of radius 3.

Any help would be much appreciated. Thanks!

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- Sep 26th 2010, 06:19 AMYehiaFinding planes that intersect spheres in 3D vector Geometry
If you are given the sphere: x²+y²+z²+x-6z=0 and the plane x+y+=0

how do you find the planes which are parallell to that plane which intersect the sphere to create circles of radius 3.

Any help would be much appreciated. Thanks! - Sep 26th 2010, 10:37 AMOpalg
The circle is , with centre at and radius . A plane that intersects it in a circle of radius 3 must have distance from the centre of the sphere (by Pythagoras). So you are looking for a plane with equation , where k is chosen so that the distance from to the plane is 1/2.