Hi, everybody, i would like to use your help with thease two problems:

1. there is a regular triangle ABC drawn in the circle. one point D is chosen on the arch AB. prove that AD+DB=DC.

2. there is a triangle ABC and BD is a median. point T is on the BC. $\displaystyle \frac{BT}{TC} = \frac{3}{1}

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BD and AT crosses in point M. calculate $\displaystyle \frac{AM}{MT}=?$