How much is x ?

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- Jan 8th 2006, 06:32 AMtotalnewbieTriangle
How much is x ?

- Jan 8th 2006, 07:23 AMCaptainBlack
You have similar triangles: Triangle $\displaystyle BDE$ is similar to triangle $\displaystyle BAC$.

So:

$\displaystyle \frac{BD}{AB}=\frac{DE}{AC}$,

or:

$\displaystyle \frac{AB-x}{AB}=\frac{x}{AC}$.

From which you should be able to find $\displaystyle x$.

RonL