Where is D in the diagram?
If SQ is parallel to BC, then the triangles ASQ and ABC are similar. Then
SQ/BC = AS/AB.
AS=2cm, SB=4cm, BC=15cm
*DQ is a typo. It should be SQ. Many apologies.
Greetings everyone. PythagorasNeophyte here.
I am doubtful of part 1 - I don't know what formula(s) must be used in finding the answer in part 1. But I am very categorical that there must be similar sides in this diagram. For example, SQ is similar to BC. That is true. Nevertheless, SQ cannot be found.
Is there any way to find SQ?
As for part 2, the answer would be triangle SQA and triangle RQA.