Hello, ragnar!
If you had made a sketch, you would have seen skeeter's FYI immediately.
$\displaystyle \text{Find a point equidistant from the points: }\;P(3, 2),\,Q(3, \text{}3),\; R(\text{}2, 2).$
Code:

(2,2)  (3,2)
o            o P
*  
*  
       *          
 ♥ 
 * 
 * 
 * 
 * Q
 (3,3)
$\displaystyle \,PQR$ is a right triangle.
Therefore, the circumcenter is the midpoint of the hypotenuse:
. . . $\displaystyle \left(\frac{1}{2},\:\frac{1}{2}\right)$