Point M is the middle of the side BC of an acute-angles triangle ABC. Point K is on the side BC and http://www.mymathforum.com/cgi-bin/m...0=%20%3C%20KAC. On section AK there is a point E and http://www.mymathforum.com/cgi-bin/m...0=%20%3C%20BAC. Prove that http://www.mymathforum.com/cgi-bin/m...0=%20%3C%20BAC.

(Symbol "<" means an angle)

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