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Math Help - problem involving guessing of jellybeans

  1. #1
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    problem involving guessing of jellybeans


    A music store offers a prize to a customer who can guess the closest, the number of jelly beans that fill a litre jar on the counter. Estimate the number of jelly beans in the jar if 1 jelly bean is approximately 2 cm long (h) by 1.5 cm in diameter (d).
    Volume = h x π x (d/2)2 (if you donít have π on your calculator, use 3.1416 instead)
    NB: 1 litre = 1000 cm
    3,

    i got
    2cm x 3.1416 x (d/2)2 = 3.53 jelly beans
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  2. #2
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    Quote Originally Posted by vegito12 View Post
    A music store offers a prize to a customer who can guess the closest, the number of jelly beans that fill a litre jar on the counter. Estimate the number of jelly beans in the jar if 1 jelly bean is approximately 2 cm long (h) by 1.5 cm in diameter (d).
    Volume = h x π x (d/2)2 (if you donít have π on your calculator, use 3.1416 instead)
    NB: 1 litre = 1000 cm
    3,

    i got
    2cm x 3.1416 x (d/2)2 = 3.53 jelly beans
    Calculate (Volume of jar)/(Volume of jelly bean).
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  3. #3
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    Well using common sense, a 1 litre jar will fit more than 3.53 jelly beans...

    3.53 isn't the number of jellybeans, it is the volume of each average jellybean.
    As mr fantastic said, use:

    \mbox{Number of Jellybeans} = \frac{\mbox{Volume of Jar}}{\mbox{Volume of each Jellybean}}
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