Given a triangle ABC and a point 'D' divides the side AB such that a triangle ADC is formed & AD/DB=1/3. If the area of the triangle ABC is r, then find the area of the triangle ADC in terms of r?
AD/DB=1/3, so think of line AB as being divided into 4 equal segments, and that each of the three points dividing the line segments on AB have a straight line connecting to point C, creating 4 equal triangles within the triangle ABC, ADC being one of those
therefore, triangle ADC=(1/4)r