# Math Help - checking work

1. ## checking work

Given a rectangle of length L and width is 20% of length. If the area of the rectangle is ‘x’, then find its perimeter in terms of x?

I get
$2.40\sqrt{\frac{x}{5}}$

2. I'm getting $2.4 \sqrt{5x}$.

If L is the length, then the width would be L/5. So

\begin{aligned}
A &= lw \\
x &= L \cdot \dfrac{L}{5} \\
5x &= L^2 \\
L &= \sqrt{5x}
\end{aligned}

...
Then find the perimeter.

3. I realized my error! sorry! thx eumyang!