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Math Help - checking work

  1. #1
    Senior Member sfspitfire23's Avatar
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    checking work

    Given a rectangle of length L and width is 20% of length. If the area of the rectangle is x, then find its perimeter in terms of x?

    I get
    2.40\sqrt{\frac{x}{5}}
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  2. #2
    Senior Member eumyang's Avatar
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    I'm getting 2.4 \sqrt{5x}.

    If L is the length, then the width would be L/5. So

    \begin{aligned}<br />
A &= lw \\<br />
x &= L \cdot \dfrac{L}{5} \\<br />
5x &= L^2 \\<br />
L &= \sqrt{5x}<br />
\end{aligned}
    ...
    Then find the perimeter.
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  3. #3
    Senior Member sfspitfire23's Avatar
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    I realized my error! sorry! thx eumyang!
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