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Thread: checking work

  1. #1
    Senior Member sfspitfire23's Avatar
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    checking work

    Given a rectangle of length L and width is 20% of length. If the area of the rectangle is x, then find its perimeter in terms of x?

    I get
    $\displaystyle 2.40\sqrt{\frac{x}{5}}$
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  2. #2
    Senior Member eumyang's Avatar
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    I'm getting $\displaystyle 2.4 \sqrt{5x}$.

    If L is the length, then the width would be L/5. So

    $\displaystyle \begin{aligned}
    A &= lw \\
    x &= L \cdot \dfrac{L}{5} \\
    5x &= L^2 \\
    L &= \sqrt{5x}
    \end{aligned}$
    ...
    Then find the perimeter.
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  3. #3
    Senior Member sfspitfire23's Avatar
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    I realized my error! sorry! thx eumyang!
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