Given a rectangle of length L and width is 20% of length. If the area of the rectangle is ‘x’, then find its perimeter in terms of x? I get $\displaystyle 2.40\sqrt{\frac{x}{5}}$
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I'm getting $\displaystyle 2.4 \sqrt{5x}$. If L is the length, then the width would be L/5. So $\displaystyle \begin{aligned} A &= lw \\ x &= L \cdot \dfrac{L}{5} \\ 5x &= L^2 \\ L &= \sqrt{5x} \end{aligned}$ ... Then find the perimeter.
I realized my error! sorry! thx eumyang!
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