Greetings to Forum Members, Im kinda stucked in this question so i guess i need some help...

The Informations :

In the diagram, ABE, ADF, BCF and DCE are straight lines. <AED = 30degrees and <AFB = 34degrees. Find <x.

The attempt at a solution :

Since they are Straight Lines,

**< EBC = 90degrees **and thus, < BCE = 60 degrees.

Since <BCE = 60 degrees, <DCF = 60degrees ( vertically opp. angles )

Since <DCF = 60degrees, < CDF = 180 - 34 - 60 = 86 degrees. ( sum of angles in triangle )

Since < CDF = 86 degrees , < ADB = 180 - 86 = 94 degrees.

Therefore, < x = 180 - 94 = 86 degrees ( angles in the opposite segment )

The Problem :

I counter-checked against the answer and i was wrong. Or rather, i do not have enough clues to solve this question. Can someone please ' enlighten ' me ?? Thanks

P/S : Sorry for the inconvenience for having to view my solutions and the question separately as i have no idea on how to have the image shown together with the post.