Find the lateral area of a regular triangular pyramid with base edge 3 in. and slant height 6 in.

Here's how I worked it out. Please tell me if this is correct. If it isn't please explain why and how to get the right answer. Thank you!

V=1/3*s^2*h

s=3

h=6

V=1/3*3^2*6

= 1/3*9*6

V=18