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Math Help - Hexagon :(

  1. #1
    Junior Member whytechocolate01's Avatar
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    Exclamation Hexagon :(

    Find the area of a regular hexagon with side 2 sqrt 3 cm. and apothem 3 cm. I really have no idea how to work this one out. Any help would be greatly appreciated! Thanks in advance!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by whytechocolate01 View Post
    Find the area of a regular hexagon with side 2 sqrt 3 cm. and apothem 3 cm. I really have no idea how to work this one out. Any help would be greatly appreciated! Thanks in advance!
    one formula for the area of a regular polygon is:

    Area = (1/2)(apothem)(perimeter)

    we are given the apothem, the perimeter is just the length of all the sides.

    let A be the apothem, and P be the permeter.

    then A = 3

    and P = 6*2sqrt(3) = 12sqrt(3)

    so we have,

    Area = (1/2)AP
    .......= (1/2)*3*12sqrt(3) cm^2
    .......= 18sqrt(3) cm^2


    see Area of a Regular Polygon and Regular polygon area formula for more info
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  3. #3
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    Hello, whytechocolate!

    Find the area of a regular hexagon with side 2√3 cm. and apothem 3 cm.
    Did you make a sketch?


    You will find that a regular hexagon is made up of six equilateral triangles.

    Each triangle has a base of 2√3 and a height of 3.

    Can you finish it now?

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