Find the area of a rectangle with length 4 and diagonal 5...
I thought this was impossible because the diagonal must be longer than the length of a side so i'm not sure what to do. Please help!
1. The area of a rectangle can be calculated by: A = length * width.
You know already: l = 4
2. The diagonal d divides the rectangle into 2 right triangles. The diagonal is the hypotenuse of the triangle. Use Pythagorean theorem to calculate the missing side w:
d² = l² + w² ==> w² = d² - l² ==> w = √(d² - l²)
Therefore w = √(5² - 4²) = √(25 - 16) = √(9) = 3
3. Plug in the values into the formula: A = 4 * 3 = 12 square units