If O is the center of the circle, BC = 10 and OC = 13, find OA. Please explain! Thank you so much for any help!
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Originally Posted by IHATECHONGAS If O is the center of the circle, BC = 10 and OC = 13, find OA. Please explain! Thank you so much for any help! The line OA intersects the chord BC at a right angle. Thus A is the midpoint of BC. Can you take it from here? -Dan
So OA = 5?...I think lol
Originally Posted by IHATECHONGAS So OA = 5?...I think lol No, AC = 5, since A is the midpoint of BC which is 10 units long. We need to use Pythagoras' Theorem to find OA. By Pythagoras' Theorem: OA^2 = 13^2 - 5^2 = 169 - 25 = 144 => OA = sqrt(144) = 12
Thank you very much for the explaination! I was so confused! lol Thanx a mil!
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