RF Technology and Triangles

I'm pretty bad at math, I can't remember any equations, since I haven't taken it in a long time. So here's my question

You have a 90 degree triangle with C1, C2, and hypotenuse representing a house, a tower, and the ray the RF tower is shooting towards the house.

Person A Lives on the point where c1, and hypotenuse met, the tower is c2.

Measurements are 3,563 feet between the house and tower(C1), The tower is 87 feet high, and ray is 3564 long. Now I work out attenuation issues, so I need to figure out at what lenth of c1, is the height of the hypotenuse. This is to figure out if the RF ray may having hitting a 30 foot tree that's in the way. Thank for you your help.

use the Pythagoran theorem when the info is there

still not sure if I have this understood. but assume you mean c1 to be the base the c2 the ht of the tower.

so the new hypotenuse using 2500ft as a base and the tower of 87ft

is simply

$\displaystyle

(2500)^2 + (87)^2 = hypotenuse^2 \Rightarrow 2501ft

$

bear in mind that this triangle is very thin, you can use ratio's to solve but much easier to use the Pythagoran theorem when the info is there

again too i may not have the correct understanding of your question

but hope this helps