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Math Help - X degrees in circles

  1. #1
    Junior Member
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    Unhappy X degrees in circles

    Solve for x degrees. Please explain the process. Thank you so very much!

    Regards,
    IHATECHONGAS
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  2. #2
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    Hello, IHATECHONGAS!

    For the last two, there is a theorem.

    From an external point, draw two secants to a circle
    . . (or two tangents or a sectant and a tangent).
    The angle formed is one-half the difference of the intercepted arcs.

    In #2, we have a secant and a tangent forming a 20 angle.
    . . The intercepted arcs are 60 and x.
    So we have: .(x - 60) .= .20 . . x = 100

    In #3, we have two tangents forming a 52 angle.
    . . The intercepted arcs are x and 360-x.
    You finish it . . .

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  3. #3
    Junior Member
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    Exclamation

    This is what I got...

    1. x = 20

    110 + x = 65 *2 = 130
    130 - 110 = 20

    3. (360 -x) - x = 104/2 = 52
    360 -128 - 128 = 104/2 = 52
    x = 128

    Is that correct?
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