Solve for x degrees. Please explain the process. Thank you so very much!

Regards,

IHATECHONGAS

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- May 11th 2007, 07:20 PMIHATECHONGASX degrees in circles
Solve for x degrees. Please explain the process. Thank you so very much!

Regards,

IHATECHONGAS - May 12th 2007, 02:42 AMSoroban
Hello, IHATECHONGAS!

For the last two, there is a theorem.

From an external point, draw two secants to a circle

. . (or two tangents or a sectant and a tangent).

The angle formed is one-half the difference of the intercepted arcs.

In #2, we have a secant and a tangent forming a 20° angle.

. . The intercepted arcs are 60° and x.

So we have: .½(x - 60) .= .20 . → . x = 100

In #3, we have two tangents forming a 52° angle.

. . The intercepted arcs are x and 360-x.

You finish it . . .

- May 12th 2007, 04:18 PMIHATECHONGAS
This is what I got...

1. x = 20

110 + x = 65 *2 = 130

130 - 110 = 20

3. (360 -x) - x = 104/2 = 52

360 -128 - 128 = 104/2 = 52

x = 128

Is that correct?:o