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Math Help - A proof is needed

  1. #1
    Senior Member Mukilab's Avatar
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    A proof is needed

    ABCD is a square.
    BEC and DCF are equilateral triangles on the east and south side of the square respectively.

    Having proved ECD=BCF I now need to prove that ED=EG. Got as far as FG=BE and angle CFE= angle EBC
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  2. #2
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    Hello, Mukilab!

    ABCD is a square.

    BEC and DCF are equilateral triangles on the east and south side of the square, resp.

    Having proved \angle ECD\,=\, \angle BCF, I now need to prove that ED=EG. .?
    Code:
         A             B
          o - - - - - o
          |           |  *
          |           |     *
          |           |        o E
          |           |     *
          |           |  *
          o - - - - - o
         D *         * C
            *       *
             *     *
              *   *
               * *
                o
                F

    Where is point G ?

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  3. #3
    Senior Member Mukilab's Avatar
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    I don't know exactly but if BFGE is a parallelogram then I guessed it would be somewhere to the south-east of F


    (Doesn't show it in any sort of diagram)
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  4. #4
    MHF Contributor
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    Quote Originally Posted by Mukilab View Post
    I don't know exactly but if BFGE is a parallelogram then I guessed it would be somewhere to the south-east of F


    (Doesn't show it in any sort of diagram)
    If BFGE is a parallelogram, then BF=GE,
    so you only need to show that ED=BF as that means ED=GE.
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