Thread: A proof is needed

ABCD is a square.
BEC and DCF are equilateral triangles on the east and south side of the square respectively.

Having proved ECD=BCF I now need to prove that ED=EG. Got as far as FG=BE and angle CFE= angle EBC

Hello, Mukilab!

is a square.

and are equilateral triangles on the east and south side of the square, resp.

Having proved , I now need to prove that .?

Code:

     A             B
      o - - - - - o
      |           |  *
      |           |     *
      |           |        o E
      |           |     *
      |           |  *
      o - - - - - o
     D *         * C
        *       *
         *     *
          *   *
           * *
            o
            F

Where is point ?

I don't know exactly but if BFGE is a parallelogram then I guessed it would be somewhere to the south-east of F


(Doesn't show it in any sort of diagram)

Originally Posted by Mukilab

I don't know exactly but if BFGE is a parallelogram then I guessed it would be somewhere to the south-east of F


(Doesn't show it in any sort of diagram)

If BFGE is a parallelogram, then BF=GE,
so you only need to show that ED=BF as that means ED=GE.