# A proof is needed

• June 5th 2010, 12:51 PM
Mukilab
A proof is needed
ABCD is a square.
BEC and DCF are equilateral triangles on the east and south side of the square respectively.

Having proved ECD=BCF I now need to prove that ED=EG. Got as far as FG=BE and angle CFE= angle EBC
• June 5th 2010, 03:25 PM
Soroban
Hello, Mukilab!

Quote:

$ABCD$ is a square.

$BEC$ and $DCF$ are equilateral triangles on the east and south side of the square, resp.

Having proved $\angle ECD\,=\, \angle BCF$, I now need to prove that $ED=EG.$ .?

Code:

```    A            B       o - - - - - o       |          |  *       |          |    *       |          |        o E       |          |    *       |          |  *       o - - - - - o     D *        * C         *      *         *    *           *  *           * *             o             F```

Where is point $G$ ?

• June 6th 2010, 01:41 AM
Mukilab
I don't know exactly but if BFGE is a parallelogram then I guessed it would be somewhere to the south-east of F

(Doesn't show it in any sort of diagram)
• June 6th 2010, 03:39 AM