ABCD is a square.

BEC and DCF are equilateral triangles on the east and south side of the square respectively.

Having proved ECD=BCF I now need to prove that ED=EG. Got as far as FG=BE and angle CFE= angle EBC

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- Jun 5th 2010, 11:51 AMMukilabA proof is needed
ABCD is a square.

BEC and DCF are equilateral triangles on the east and south side of the square respectively.

Having proved ECD=BCF I now need to prove that ED=EG. Got as far as FG=BE and angle CFE= angle EBC - Jun 5th 2010, 02:25 PMSoroban
Hello, Mukilab!

Quote:

$\displaystyle ABCD$ is a square.

$\displaystyle BEC$ and $\displaystyle DCF$ are equilateral triangles on the east and south side of the square, resp.

Having proved $\displaystyle \angle ECD\,=\, \angle BCF$, I now need to prove that $\displaystyle ED=EG.$ .?

Code:`A B`

o - - - - - o

| | *

| | *

| | o E

| | *

| | *

o - - - - - o

D * * C

* *

* *

* *

* *

o

F

Where is point $\displaystyle G$ ?

- Jun 6th 2010, 12:41 AMMukilab
I don't know exactly but if BFGE is a parallelogram then I guessed it would be somewhere to the south-east of F

(Doesn't show it in any sort of diagram) - Jun 6th 2010, 02:39 AMArchie Meade