For problem 12 we now have a new side BE congruent to BD. We already have the angle adjacent to BE, angle ABE congruent to angle CBD. And we have AB congruent to CB. So this is side, angle, side.
For problem 13 there are two adjacent sides and an angle, so that would be SSA, however there is no such theorem that proves congruency. So that answer would be D.
These are pretty straightforward problems. If you are having a lot of trouble, please seek additional help. I can try to help find that help for you if you do not have additional resources.