The area of a rectangle is 64 and the base is 4√2 What is the perimeter of the rectangle? A 32√2 b 24√2 c 16√2 d 12 √2 e 8 √2
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Originally Posted by sri340 The area of a rectangle is 64 and the base is 4√2 What is the perimeter of the rectangle? A 32√2 b 24√2 c 16√2 d 12 √2 e 8 √2 Hi sri340, Use A = LW to find the missing side. $\displaystyle 64=4\sqrt{2}\:W$ $\displaystyle W=8\sqrt{2}$ Now, you know L and W. Use P = 2L + 2W.
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