Ok, can someone help me out here? kinda stuck

http://www.usatestprep.com/images/audio_icon_small2.gif Determine the length of arc JL.

A)

59

12

π

B)

5

6

π

C)

13

12

π

D)

13

6

π

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- Jun 2nd 2010, 12:15 PMallsmilescirlces and detrmineing the length
Ok, can someone help me out here? kinda stuck

http://www.usatestprep.com/images/audio_icon_small2.gif Determine the length of arc JL.

A)

59

12

π

B)

5

6

π

C)

13

12

π

D)

13

6

π - Jun 2nd 2010, 12:30 PMe^(i*pi)
For degrees the arc length x can be found by $\displaystyle \frac{x}{2\pi r} = \frac{\theta}{360}$

Where x is arc length, $\displaystyle r$ is the radius and $\displaystyle \theta$ the angle subtended

Incidentally it's much easier in radians because $\displaystyle x = r \theta$