Get corner points from bounding box and rotation.

I assume there is a tilted rectangle in the figure. If so, then the answer is to your question is yes, it is possible.

I assume you want to know how?

(You should write more specifically.)

Here is one way. Refer to my attachment.

L and H are known, from the coordinates circled in red.

We have similar triangles.

$\frac{w}{z} = \frac{y}{x}$

Also,

$x+w=L$

$y+z=H$

Substitute

$\frac{L-x}{H-y} = \frac{y}{x}$

$x^2-y^2-Lx+Hy=0$

We know that

$\tan 25^\circ=\frac{y}{x}$

We can now solve for $x$ (discard the value $x=0$ ). From this we can obtain the values of all variables.

When L = 7.5 and H = 8.5, I get $x \approx 4.51901$ .