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Math Help - Special Triangles

  1. #1
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    Exclamation Special Triangles

    Find the value of x in these special triangles. Please help.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by pow3r2dapplz View Post
    Find the value of x in these special triangles. Please help.
    for the first question:

    we will use trig ratios to do this:

    for the left triangle:

    cos(45) = adj/hyp = 4/x

    => sqrt(2)/2 = 4/x
    => 4/(sqrt(2)/2) = x
    => x = 8/sqrt(2) = 4sqrt(2)

    for the triangle on the right:

    cos(60) = adj/hyp = 5/x
    => 1/2 = 5/x
    => x = 10
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by pow3r2dapplz View Post
    More....
    for the second question:

    same idea:

    for the triangle on the left:

    sin(45) = opp/hyp = x/14
    => sqrt(2)/2 = x/14
    => x = 7sqrt(2)

    for the one on the right, we use Pythagoras' theorem

    x^2 = 12^2 - 6^2 = 144 - 36 = 108
    => x = sqrt(108)
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