Find the value of x in these special triangles. Please help.
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Originally Posted by pow3r2dapplz Find the value of x in these special triangles. Please help. for the first question: we will use trig ratios to do this: for the left triangle: cos(45) = adj/hyp = 4/x => sqrt(2)/2 = 4/x => 4/(sqrt(2)/2) = x => x = 8/sqrt(2) = 4sqrt(2) for the triangle on the right: cos(60) = adj/hyp = 5/x => 1/2 = 5/x => x = 10
Originally Posted by pow3r2dapplz More.... for the second question: same idea: for the triangle on the left: sin(45) = opp/hyp = x/14 => sqrt(2)/2 = x/14 => x = 7sqrt(2) for the one on the right, we use Pythagoras' theorem x^2 = 12^2 - 6^2 = 144 - 36 = 108 => x = sqrt(108)
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