http://www.boardofstudies.nsw.edu.au...hs_ext1_05.pdf

with explanation and reasons please question 3d

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- May 21st 2010, 07:19 AMandy69circle geometry help 4
http://www.boardofstudies.nsw.edu.au...hs_ext1_05.pdf

with explanation and reasons please question 3d - May 21st 2010, 10:57 AMspruancejr
What do you specifically do not understand?

- May 21st 2010, 05:38 PMandy69
- May 21st 2010, 11:59 PMsa-ri-ga-ma
When the two chords Ab and CD intersect each other at E, they satisfy the following condition.

$\displaystyle \frac{AE}{EB} = \frac{CE}{ED}$ .............(1)

AE = 4, AB = 7. So EB = ...?

CD = l, ED = x, so CE = ...?

Substitute these values in equation (1) and simplify.

The equation obtained is

$\displaystyle x^2 - lx + 12 = 0.$ Or

$\displaystyle l = x + \frac{12}{x}$

To get the minimum length of the chord CD, find dl/dx and equate it to zero. Then solve for x. Substitute this value in eq.(1) to find CF, then find CD. - May 22nd 2010, 01:15 AMandy69
- May 22nd 2010, 02:05 AMsa-ri-ga-ma
- May 22nd 2010, 07:17 AMandy69
- May 22nd 2010, 05:15 PMsa-ri-ga-ma
- May 22nd 2010, 06:13 PMandy69
- May 22nd 2010, 06:43 PMWilmer
- May 22nd 2010, 07:45 PMsa-ri-ga-ma
- May 22nd 2010, 10:28 PMandy69
- May 22nd 2010, 10:32 PMsa-ri-ga-ma
- May 22nd 2010, 10:38 PMandy69
- May 23rd 2010, 03:45 AMsa-ri-ga-ma