Find the values of x. For number one... Given: p ll q For number two... Given: p ll q ll r Nothing given for three...
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For the 1st problem: x = 10 Because 3/5 = 6/x Simplify that and you get x = 10 I'll work on the rest. Geometry isnt my strongest point
Originally Posted by whytechocolate01 Find the values of x. For number one... Given: p ll q For number two... Given: p ll q ll r Nothing given for three... In 1 we have similiar triangles. (x + 6)/6 = (5 + 3)/3 3(x + 6) = 6(8) 3x + 18 = 48 3x = 30 x = 10
Originally Posted by whytechocolate01 Find the values of x. For number one... Given: p ll q For number two... Given: p ll q ll r Nothing given for three... For problem 2, we can set up a ratio between the outer sides of the two trapezoids: 10/5 = 14/x 2x = 14 x = 7
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