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Math Help - rearranging equasions

  1. #1
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    rearranging equasions

    Morning, I have not studied maths for some time now and need some help rearranging the 2 following equations.

    1. y=8-2x

    2. 3y+2x=-12

    Your help is appreciated
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  2. #2
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    Quote Originally Posted by henry View Post
    Morning, I have not studied maths for some time now and need some help rearranging the 2 following equations.

    1. y=8-2x

    2. 3y+2x=-12

    Your help is appreciated
    How are we arranging them?

    Are the part of a linear system; therefore, we need to solve them simultaneously?
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  3. #3
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    Quote Originally Posted by henry View Post
    Morning, I have not studied maths for some time now and need some help rearranging the 2 following equations.

    1. y=8-2x

    2. 3y+2x=-12

    Your help is appreciated
    I suppose you want to make x the subject...

    y = 8 - 2x

    y + 2x = 8

    2x = 8 - y

    x = \frac{8 - y}{2}

    x = 4 - \frac{y}{2}.
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    i need to find the slope, x intercept and y intercept of both equations
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    Quote Originally Posted by dwsmith View Post
    How are we arranging them?

    Are the part of a linear system; therefore, we need to solve them simultaneously?

    i need to find the slope, x intercept and y intercept of both equations
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  6. #6
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    You can read off the slope and y intercept in the first one, because it is already in y = mx + c form... m is the slope and c is the y intercept...

    y = -2x + 8.

    To find the x intercept, let y = 0 and solve for x.


    For the second

    3y + 2x = -12

    3y = -2x - 12

    y = -\frac{2}{3}x - 4.

    Now you can do the same process as the first question.
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