Morning, I have not studied maths for some time now and need some help rearranging the 2 following equations.
1. y=8-2x
2. 3y+2x=-12
Your help is appreciated
You can read off the slope and $\displaystyle y$ intercept in the first one, because it is already in $\displaystyle y = mx + c$ form... $\displaystyle m$ is the slope and $\displaystyle c$ is the $\displaystyle y$ intercept...
$\displaystyle y = -2x + 8$.
To find the $\displaystyle x$ intercept, let $\displaystyle y = 0$ and solve for $\displaystyle x$.
For the second
$\displaystyle 3y + 2x = -12$
$\displaystyle 3y = -2x - 12$
$\displaystyle y = -\frac{2}{3}x - 4$.
Now you can do the same process as the first question.