Hey, I must be an idiot because the answer to this is probably simple. Anywho. Circle has equation X^2+y^2+4x-8y+10=0 So Center is (-2,4) and Radius is Route 10. Now L has an equation X-3y+4=0 All I have to do is show that L is a tangent to C.
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Originally Posted by StephenPoco Hey, I must be an idiot because the answer to this is probably simple. Anywho. Circle has equation X^2+y^2+4x-8y+10=0 So Center is (-2,4) and Radius is Route 10. Now L has an equation X-3y+4=0 All I have to do is show that L is a tangent to C. If L is a tangent to C then they must have a common point, say . Common point means: Now solve these two equations simultaneously. Then will satisfy both and be the required common point.
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