Thread: Kindly help me for this triangle problem

The problem is attached. It is triangle and its peak is having value 1

the sides are at a and -a. The new point is on a/4. from which i have drawn perpendicular line

i want to know what is the value of that point on y-axis scale.
book says it is 0.733
but how???

The problem is attached. It is triangle and its peak is having value 1

the sides are at a and -a. The new point is on a/4. from which i have drawn perpendicular line

i want to know what is the value of that point on y-axis scale.
book says it is 0.733
but how???

Since I would consider this a typical proportional problem, I wonder that too?
Are you sure you don't have any more information on a?

If a can be any number, triangle height y can be 0<y<1 ?

Originally Posted by moonnightingale

The problem is attached. It is triangle and its peak is having value 1

the sides are at a and -a. The new point is on a/4. from which i have drawn perpendicular line

i want to know what is the value of that point on y-axis scale.
book says it is 0.733
but how???

The two known points on that line segment are

and .

The gradient is





.


The intercept is , so .


Therefore the line segment has equation



.


So if





.

one can do that?
isn't that like saying a=y=1 ?

so all you get is a mirror?
y = 1-x ?

I'm asking since I really don't know.

//====edit
aren't you supposed to plug that back to the equation? so that:
3/4 = -(1/a)x + 1

//====edit 2
wow, that was really stupid of me of course 3/4