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Math Help - Kindly help me for this triangle problem

  1. #1
    Member moonnightingale's Avatar
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    Kindly help me for this triangle problem

    The problem is attached. It is triangle and its peak is having value 1

    the sides are at a and -a. The new point is on a/4. from which i have drawn perpendicular line

    i want to know what is the value of that point on y-axis scale.
    book says it is 0.733
    but how???
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  2. #2
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    The problem is attached. It is triangle and its peak is having value 1

    the sides are at a and -a. The new point is on a/4. from which i have drawn perpendicular line

    i want to know what is the value of that point on y-axis scale.
    book says it is 0.733
    but how???
    Since I would consider this a typical proportional problem, I wonder that too?
    Are you sure you don't have any more information on a?

    If a can be any number, triangle height y can be 0<y<1 ?
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  3. #3
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    Quote Originally Posted by moonnightingale View Post
    The problem is attached. It is triangle and its peak is having value 1

    the sides are at a and -a. The new point is on a/4. from which i have drawn perpendicular line

    i want to know what is the value of that point on y-axis scale.
    book says it is 0.733
    but how???
    The two known points on that line segment are

    (a, 0) and (0, 1).

    The gradient is

    m = \frac{1 - 0}{0 - a}

     = \frac{1}{-a}

     = -\frac{1}{a}.


    The y intercept is 1, so c = 1.


    Therefore the line segment has equation

    y = -\frac{1}{a}\,x + 1

    y = 1 - \frac{x}{a}.


    So if x = \frac{a}{4}

    y = 1 - \frac{\frac{a}{4}}{a}

     = 1 - \frac{1}{4}

     = \frac{3}{4}.
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  4. #4
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    one can do that?
    isn't that like saying a=y=1 ?

    so all you get is a mirror?
    y = 1-x ?

    I'm asking since I really don't know.

    //====edit
    aren't you supposed to plug that back to the equation? so that:
    3/4 = -(1/a)x + 1

    //====edit 2
    wow, that was really stupid of me of course 3/4
    Last edited by ellensius; May 14th 2010 at 03:42 PM.
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