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Math Help - Parallelogram Help

  1. #1
    Junior Member whytechocolate01's Avatar
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    Exclamation Parallelogram Help

    In parallelogram ABCD the measure of angle ABC=60

    Find the measure of angle DAB

    If measure ADB=32, find the measure of angle ABD

    If DE=14, find DB

    If AD=6x-5 and BC=4x+7, find x

    Please explain!
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  2. #2
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    I shouldn't be answering any questions...

    -
    All angles in parallelogram add up to 360.
    ABC = 60
    ADC = 60
    ABC + ADC = 120
    360 - 120 = 240
    Therefore
    DAB + DCB = 240
    To get DAB divide 240 by 2. 240/2 = 120

    -
    "If measure ADB=32, find the measure of angle ABD"

    I presume you mean angle ADB = 32. ABD should be equale it, 32.
    ---
    DE=14
    DB = 2(DE) = 28
    ------
    AD=6x-5 and BC=4x+7
    AD should be equal to BD
    6x-5 = 4x+7
    Take x to one side,
    6x - 4x = 7 + 5
    2x = 12
    x = 6


    Edit: 3/4 right
    Last edited by r_maths; May 1st 2007 at 10:52 AM.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by whytechocolate01 View Post
    In parallelogram ABCD the measure of angle ABC=60

    Find the measure of angle DAB
    r_maths answered this question

    If measure ADB=32, find the measure of angle ABD
    we found that DAB is 120, hopefully r_maths was right, i didn't really check his work. so now, we are concerned with the angles in triangle ABD. one angle is 120 (i said that before) and the other angle is givwen to be 32. the angles in a triangle add up to be 180, so,

    ABD = 180 - (120 + 32) = 28

    If DE=14, find DB
    Since this is a parallelogram, DE = EB, and so,
    DB = 2DE = 2*14 = 28

    If AD=6x-5 and BC=4x+7, find x
    Since this is a parallelogram, AD = BC

    so we have,

    6x - 5 = 4x + 7
    => 2x = 12
    => x = 6
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  4. #4
    Junior Member whytechocolate01's Avatar
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    Thank you

    Thank you both for your help. Now I actually understand this! Thanks a mil!
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