In parallelogram ABCD the measure of angle ABC=60
Find the measure of angle DAB
If measure ADB=32, find the measure of angle ABD
If DE=14, find DB
If AD=6x5 and BC=4x+7, find x
Please explain!
I shouldn't be answering any questions...

All angles in parallelogram add up to 360.
ABC = 60
ADC = 60
ABC + ADC = 120
360  120 = 240
Therefore
DAB + DCB = 240
To get DAB divide 240 by 2. 240/2 = 120

"If measure ADB=32, find the measure of angle ABD"
I presume you mean angle ADB = 32. ABD should be equale it, 32.

DE=14
DB = 2(DE) = 28

AD=6x5 and BC=4x+7
AD should be equal to BD
6x5 = 4x+7
Take x to one side,
6x  4x = 7 + 5
2x = 12
x = 6
Edit: 3/4 right
r_maths answered this question
we found that DAB is 120, hopefully r_maths was right, i didn't really check his work. so now, we are concerned with the angles in triangle ABD. one angle is 120 (i said that before) and the other angle is givwen to be 32. the angles in a triangle add up to be 180, so,If measure ADB=32, find the measure of angle ABD
ABD = 180  (120 + 32) = 28
Since this is a parallelogram, DE = EB, and so,If DE=14, find DB
DB = 2DE = 2*14 = 28
Since this is a parallelogram, AD = BCIf AD=6x5 and BC=4x+7, find x
so we have,
6x  5 = 4x + 7
=> 2x = 12
=> x = 6