# Parallelogram Help

• May 1st 2007, 09:19 AM
whytechocolate01
Parallelogram Help
In parallelogram ABCD the measure of angle ABC=60

Find the measure of angle DAB

If measure ADB=32, find the measure of angle ABD

If DE=14, find DB

If AD=6x-5 and BC=4x+7, find x

• May 1st 2007, 09:54 AM
r_maths
I shouldn't be answering any questions...

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All angles in parallelogram add up to 360.
ABC = 60
360 - 120 = 240
Therefore
DAB + DCB = 240
To get DAB divide 240 by 2. 240/2 = 120

-
"If measure ADB=32, find the measure of angle ABD"

I presume you mean angle ADB = 32. ABD should be equale it, 32.
---
DE=14
DB = 2(DE) = 28
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AD should be equal to BD
6x-5 = 4x+7
Take x to one side,
6x - 4x = 7 + 5
2x = 12
x = 6

Edit: 3/4 right http://www.mathhelpforum.com/math-he...es/redface.gif
• May 1st 2007, 10:03 AM
Jhevon
Quote:

Originally Posted by whytechocolate01
In parallelogram ABCD the measure of angle ABC=60

Find the measure of angle DAB

Quote:

If measure ADB=32, find the measure of angle ABD
we found that DAB is 120, hopefully r_maths was right, i didn't really check his work. so now, we are concerned with the angles in triangle ABD. one angle is 120 (i said that before) and the other angle is givwen to be 32. the angles in a triangle add up to be 180, so,

ABD = 180 - (120 + 32) = 28

Quote:

If DE=14, find DB
Since this is a parallelogram, DE = EB, and so,
DB = 2DE = 2*14 = 28

Quote:

If AD=6x-5 and BC=4x+7, find x
Since this is a parallelogram, AD = BC

so we have,

6x - 5 = 4x + 7
=> 2x = 12
=> x = 6
• May 1st 2007, 10:19 AM
whytechocolate01
Thank you
Thank you both for your help. Now I actually understand this! Thanks a mil! :)