• May 1st 2007, 09:08 AM
whytechocolate01
A segment joins the midpoints of two sides of a triangle.

Find the value of x.
Find the value of y.

• May 1st 2007, 10:55 AM
topsquark
Quote:

Originally Posted by whytechocolate01
Find the value of x.
Find the value of y.

It can't be done. The smaller top triangle is similar to the large (overall) triangle, but this will only give you ratios, not specific numbers. The best I can say is that:
(3x + 2)/(10x - 4) = (3y - 18)/([3y- 18] + [2(y - 5)])

or

(3x + 2)/(10x - 4) = (3y - 18)/(5y - 28)

-Dan
• May 1st 2007, 12:48 PM
Quick
Quote:

Originally Posted by topsquark
It can't be done.

Tsk Tsk.

10x-4 = 2(3x+2)

10x-4 = 6x+4

4x = 8

x = 2

I'll tell you that:

3y-18 = 2(y-5)

but you'll have to solve for y.
• May 1st 2007, 12:53 PM
Soroban
Helllo, whytechocolate01!

Ah, those are midpoints!

Quote:

A segment joins the midpoints of two sides of a triangle.
Find the value of x and y.

Since those are midpoints: .3y - 18 .= .2(y - 5) . . y = 8

Theorem: The line segment joining midpoints of two sides of a triangle
. . is parallel to and one-half the length of the third side.

Hence, we have: .3x + 2 .= .½(10x - 4) . . x = 2

• May 1st 2007, 12:57 PM
topsquark
Quote:

Originally Posted by Soroban

Ah, those are midpoints!

:o My comment exactly!

-Dan
• May 1st 2007, 01:24 PM
IHATECHONGAS
Awesome job everyone! I had this exact question on a worksheet! LOL. Thanks to whytechocolate01 for posting this! :)
• May 1st 2007, 03:05 PM
whytechocolate01
Thanks to all!
Thank you all for helping me figure out this problem. You have all been quite helpful! :)

@ IHATECHONGAS: Hiiiiiiiiiiii! LOL. Don't mind me i'm being random... :P

Toodlez!