1. ## Please!!! Help me work it out!

A. Use a ruler to complete the drawing of triangle ABC by drawing in side BC. There are two solutions for side BC. Draw both and label one C1 and the other C2. Do this by drawing two inch lines from point B to appropriate points on the dotted line.

B. Consider triangle DEF and triangle JKL with line DE congruent to line JK, line EF congruent to line KL, and angle EDF congruent to angle KJL. Two sides and a non-included angle of one triangle are congruent to two sides and a non-included angle of the other triangle. From your solution to part A, is it correct to conclude that triangle DEF must be congruent to triangle JKL. Please explain!

2. Originally Posted by whytechocolate01
A. Use a ruler to complete the drawing of triangle ABC by drawing in side BC. There are two solutions for side BC. Draw both and label one C1 and the other C2. Do this by drawing two inch lines from point B to appropriate points on the dotted line....
Hi,

I've modified your drawing. (See attachment)

The red lines are probably not 2 inches long, be careful!

3. Originally Posted by whytechocolate01
...
B. Consider triangle DEF and triangle JKL with line DE congruent to line JK, line EF congruent to line KL, and angle EDF congruent to angle KJL. Two sides and a non-included angle of one triangle are congruent to two sides and a non-included angle of the other triangle. From your solution to part A, is it correct to conclude that triangle DEF must be congruent to triangle JKL. Please explain!
Hi,

two triangles which are congruent in two sides and the non-included angle are congruent if the longer of the two sides is opposite the angle. Because this statemant is not added the conclusion is wrong, as you can see at part A:
BC1 = BC2 but with BC the shorter of the two sides is opposite the angle and therefore triangle ABC1 is not congruent triangle ABC2

4. ## Thank you!!!

Thank you ever so much! I really appreciate it! I actually understand it now! Thanks a mil!