Thread: plz help

Hi,

May someone please help me.

Thank you.

In the figure, PE bisects angle DPF, AD is perpendicular to CG and ppoints B, P, and F are collinear. If slope angle BPC = 22, find slope angle DPE.

Originally Posted by JayJay1206

Hi,

May someone please help me.

Thank you.

In the figure, PE bisects angle DPF, AD is perpendicular to CG and ppoints B, P, and F are collinear. If slope angle BPC = 22, find slope angle DPE.

Note that angle GPF = angle BPC since they are congruent angles. so GPF = 22

since AD is perpendicular to CG, angle APG = 90

since PE bisects DPF, we have angle FPE = angle DPE, so we can write,

APG + DPE = DPE + DPE = 2DPE

now, A and D are colinear, so the su of the angles on one side of AD add up to 180 degrees, that is,

angleAPG + angleGPF + 2*angleDPE = 180
=> 90 + 22 + 2DPE = 180
=> 2DPE = 180 - 90 - 22 = 68
=> DPE = 68/2 = 34 degrees