Just a bit confused as to what to do with the following question involving a hexagon insribed in a circle, area/geometry isn't my strongest link in maths.
The question asks to find the area of the hexagon inscribed in the circle.
Like so:
NOTE: The Radius of the circle is 1cm in the question instead of 10cm.
Would really appreciate it if someone could briefly outline the steps and formulas involved in solving this question.
Cheers,
Jaz
Cheers.
And from there I just simply find the area of the circle, then I subtract the area of the hexagon from the area of the circle?
Which ends up being;
Area of circle = PieR^2 = Pie x 1^2 = 3.1415962654
Area of equilateral triangle = 1^2 square root 3 divided by 4 = 0.433012702
Total area of equilateral triangles = 0.433012702 x 6 = 2.598076211
Therefore, Total Area of Hexagon = 3.1415962654 - 2.598076211 = Final Answer
Is that correct? (Thanks for your help thus far)
What you've found is the area inside the circle but outside the hexagon (ie the 6 segments around the circumference).
Your original question just asked for the area of the hexagon, which is just the 2.59 (or more precisely 3 sqrt(3)/2).
Reread the original question to see what you want.