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Math Help - help needed with conic section and hyperbolas

  1. #1
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    Question help needed with conic section and hyperbolas

    Given the equation x^2-4y^2-2x-8y-7=0 how do you find the coordinates of the center of the hyperbola? Thanks for the help in advance!
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  2. #2
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    x^2 -4y^2 -2x-8y-7=0;
    x^2 -2x +1 - 1 - (4x^2 + 8x +4) +4 -7 = 0;
    (x-1)^2- (2y+2)^2 =4;
    \frac{(x-1)^2}{4} - 4\cdot \frac{(y+1)^2}{4}=1;

    \frac{(x-1)^2}{4} - \frac{(y+1)^2}{1}=1 ( standard equation of the hyperbola is \frac{(x-x_0)^2}{a^2} - \frac{(y-y_0)^2}{b^2}=1, center is  (x_0, y_0))

    Center for our hiperbola is: (1, -1).
    Last edited by veljko; April 30th 2010 at 12:48 PM.
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