Geometry Problem (may possibly require calculus, but probably not)

Here is the problem:

Consider the circle x^2 + y^2 - 2sqrt(3)x -2y +3 = 0 and two lines y=1/sqrt(3)x and y=sqrt(3)x drawn on the same Cartesian coordinate system. What is the area of the region that is bounded b the two lines and the circle, and that is lying in the exterior of the circle?

I know the lines are 30 and 60 degrees from the positive x axis (trisect the first quadrant) and the circle is radius 1 with center at (sqrt(3),1), but I still can't figure this out. Please help