ABCD is a square and ECD an isosceles triangle
with base angles 15 degrees, as shown in the figure. Prove that Angle AEB = 60 degrees (and therefore triangle AEB is equilateral), without using trigonometry.
Is this impossible? thanks for your help.
ABCD is a square and ECD an isosceles triangle
with base angles 15 degrees, as shown in the figure. Prove that Angle AEB = 60 degrees (and therefore triangle AEB is equilateral), without using trigonometry.
Is this impossible? thanks for your help.
ABCD is a square and ECD an isosceles triangle
with base angles 15 degrees, as shown in the figure. Prove that Angle AEB = 60 degrees (and therefore triangle AEB is equilateral), without using trigonometry.
Is this impossible? thanks for your help.
Angle AED = BEC. Angle DEC = 150. AED + BEC + DEC + AEB = 360.