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Math Help - Mapping of a Circle Equation

  1. #1
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    Mapping of a Circle Equation

    I am trying to map this equation of a circle and I am wondering if it is right.

    A circle whose equation is (x-2)^2 + (y+1)^2 = 8 is translated as four unitds right and three units down. Write the equation of the new circle. Write the mapping rule that maps the unit circle to the new circle.

    So I came up with this:

    (x-6)^2 + (y+4)^2= Square root of 8^2 for the equation

    and (x,y) --> (x + 6, y - 4) for the mapping.

    Is this right?
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  2. #2
    Member pflo's Avatar
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    Quote Originally Posted by (?)G View Post
    I am trying to map this equation of a circle and I am wondering if it is right.

    A circle whose equation is (x-2)^2 + (y+1)^2 = 8 is translated as four unitds right and three units down. Write the equation of the new circle. Write the mapping rule that maps the unit circle to the new circle.

    So I came up with this:

    (x-6)^2 + (y+4)^2= Square root of 8^2 for the equation

    and (x,y) --> (x + 6, y - 4) for the mapping.

    Is this right?
    The circle moves 4 units right - this means you need to subtract 4 from the 'x' value. The circle moves 3 units down - this means you need to subtract from the 'y' value. The mapping is therefore (x,y) --> (x-4,y-3).

    When you plug these in the original equation, you get (x-6)^2 + (y-2)^2.
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