hey can someone show me how to do this problem please?
thanks
The hypotenuse of such a right triangle is sqrt(2) times the length of one of
the other sides.
So going from the side of length x clockwise the sides radiating from the
central point have lengths:
x,
x sqrt(2),
sqrt(2) (x sqrt(2)),
sqrt(2) (sqrt(2) (x sqrt(2))),
sqrt(2) (sqrt(2) (sqrt(2) (x sqrt(2))))
but this last one we are told is 4, so:
sqrt(2) (sqrt(2) (sqrt(2) (x sqrt(2)))) = 4x = 4,
so x=1.
RonL