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Math Help - Help with a special right triangles problem

  1. #1
    ashleynicolexox
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    Help with a special right triangles problem

    hey can someone show me how to do this problem please?

    thanks
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by ashleynicolexox View Post
    hey can someone show me how to do this problem please?

    thanks
    The hypotenuse of such a right triangle is sqrt(2) times the length of one of
    the other sides.

    So going from the side of length x clockwise the sides radiating from the
    central point have lengths:

    x,
    x sqrt(2),
    sqrt(2) (x sqrt(2)),
    sqrt(2) (sqrt(2) (x sqrt(2))),
    sqrt(2) (sqrt(2) (sqrt(2) (x sqrt(2))))

    but this last one we are told is 4, so:

    sqrt(2) (sqrt(2) (sqrt(2) (x sqrt(2)))) = 4x = 4,

    so x=1.

    RonL
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