Hello bemidjibasser Originally Posted by
bemidjibasser I would appreciate some insight on finding the equation of and ellipse with the x intercepts 3 and -3, y intercepts 4 and -4.
I am at a loss right now...
The general equation of an ellipse with centre the origin and axes lying along the coordinate axes is
$\displaystyle \frac{x^2}{a^2}+\frac{y^2}{b^2}=1$
Putting $\displaystyle y$ and $\displaystyle x$ in turn equal to 0, gives intercepts $\displaystyle (\pm a, 0)$ and $\displaystyle (0, \pm b)$. So, for the intercepts given here:
$\displaystyle a=3, b = 4$
and the equation is therefore:
$\displaystyle \frac{x^2}{9}+\frac{y^2}{16}=1$
Grandad