I would appreciate some insight on finding the equation of and ellipse with the x intercepts 3 and -3, y intercepts 4 and -4.

I am at a loss right now...

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- Apr 8th 2010, 08:43 AMbemidjibasserConic section of an ellipse question...
I would appreciate some insight on finding the equation of and ellipse with the x intercepts 3 and -3, y intercepts 4 and -4.

I am at a loss right now... - Apr 8th 2010, 09:50 AMGrandad
Hello bemidjibasserThe general equation of an ellipse with centre the origin and axes lying along the coordinate axes is

$\displaystyle \frac{x^2}{a^2}+\frac{y^2}{b^2}=1$Putting $\displaystyle y$ and $\displaystyle x$ in turn equal to 0, gives intercepts $\displaystyle (\pm a, 0)$ and $\displaystyle (0, \pm b)$. So, for the intercepts given here:

$\displaystyle a=3, b = 4$and the equation is therefore:

$\displaystyle \frac{x^2}{9}+\frac{y^2}{16}=1$Grandad