# Math Help - 3D

1. ## 3D

$\textup{The distance of the point (-2,3,-4) from the line}$ $\frac{x+2}{3}=\frac{2y+3}{4}=\frac{3z+4}{5}$ $\textup{measured parallel to the plane}$ $4x+12y-3z+1=0$ is ?

2. Originally Posted by banku12
$\textup{The distance of the point P(-2,3,-4) from the line}$ $\frac{x+2}{3}=\frac{2y+3}{4}=\frac{3z+4}{5}$ $\textup{measured parallel to the plane}$ $4x+12y-3z+1=0$ is ?
1. Determine the equation of a plane E passing through P and parallel to the given plane.
Spoiler:
$\bold{E:} 4x+12y-3z-40=0$

2.Calculate the coordinates of the point of intersection between the given line and the plane E.
Spoiler:
$\left(4,\ \frac52 ,\ 2\right)$

3. Calculate the distance $d=|\overline{PE}|$
Spoiler:
$d=\frac{17}2$