A sealed tank 4 feet hight with width 3 feet and length 5 feet is filled one foot deep with water. If the tank is turned on one of its smallest faces, how deep (in feet) will the water be?
I can only try and draw a picture...but that doesn't help me in any way solve the problem. To the experts I look to :-)
I don't understand how you get the volume of water to be
3*5*1 cubic feet
What formula is that for? Don't understand where the one comes from.
Also V= l*w*h
Sorry Captain Black. Just trying to make sure I am able to do these "types" of problems in general as supposed to just getting the answers. You are major help and a pro I tell you.
The width of the tank is 3ft, the length is 5 ft and it is filled to a depth of 1 ft, so the volume of water is 3*5*1 cubic ft.
When it is turned on end we have the plan size is now 4 by 3 ft, and if the depth is D the volume of water is 4*3*D which is equalk to the volume we had before.
RonL