Hello again, I have one last question I need help with. Thanks

A line passes through the point (6,6) and isperpendicularto the line whose equation in standard form is 4x - 8y = 11. Find an equation of the line in question.

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- Apr 14th 2007, 01:00 AMTroy SFinding an equation of a line
Hello again, I have one last question I need help with. Thanks

A line passes through the point (6,6) and is**perpendicular**to the line whose equation in standard form is 4x - 8y = 11. Find an equation of the line in question. - Apr 14th 2007, 02:17 AMCaptainBlack
The slope of the line 4x - 8y = 11, is 1/2 (to see this rearrange it into the for

y=mx+c). So the slope of the required line is -1 divided by this ie -2.

So we seek the equation of a line through (6,6) of slope -2.

This can be written:

y = -2x + c,

and as it passess through (6,6) we have:

6 = -12 + c,

so c = 18, and the equation of the line is:

y = -2x + 18.

RonL